The mass fractions of total ferrite and total cementite in an iron-carbon alloy are 0.88 and 0.12, respectively. Is this a hypoeutectoid or hypereutectoid alloy? Why?
\(W_\alpha \) = 0.88
\(W_{Fe_{3}C} \) = 0.12
Hypoeutectoid or hypereutectoid alloy?
\( W_\alpha \) = \(C_{Fe_{3}C} - C_0 \over C_{Fe_{3}C} - C_\alpha \)
\( C_{Fe_{3}C} \) = 6.7 wt%C
\( C_{\alpha} \) = 0.022 wt%C
\(C_0 \) = \(C_{Fe_{3}C} - W_\alpha (C_{Fe_{3}C} - C_\alpha ) \)
\(C_0 \) = \(6.7 - 0.88 (6.7 - 0.022 ) \)
\(C_0\) = 0.82 wt% C
\(C_0\) > 0.76 wt% C
Hypereutectoid alloy